Question:medium

A bag contains 6 Red and 6 black balls. 6 pair of balls are selected one by one without replacement then the probability that each of the 6 pairs contains 1 red and 1 black ball.

Show Hint

For problems involving "each pair contains one of each type," think of it as a matching problem. The number of ways to match $n$ items of type A with $n$ items of type B is always $n!$.
Updated On: Apr 7, 2026
  • \(\frac{15}{231}\)
  • \(\frac{14}{231}\)
  • \(\frac{13}{231}\)
  • \(\frac{16}{231}\)
Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?
0