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A bag contains 6 blue and 6 green balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each drawn pair consists of one blue ball and one green ball is:
A bag contains 6 blue and 6 green balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each drawn pair consists of one blue ball and one green ball is:
Updated On: Apr 12, 2026
- \( \frac{63}{925} \)
- \( \frac{17}{231} \)
- \( \frac{16}{231} \)
- \( \frac{64}{925} \)
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The Correct Option is D
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