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A and B can do a work in 20 days. When A works at 60% capacity, B has to work at 150% capacity to finish the work. Find in how many days the faster one will finish the work alone.

Updated On: Nov 25, 2025
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Solution and Explanation

Let x represent the number of days required for the faster individual (assumed to be A) to complete the work independently.

When A operates at 60% capacity and B operates at 150% capacity, their combined work rate is equivalent to \( \frac{3}{5} + \frac{3}{2} \) of the standard capacity.

The equation \( (\frac{3}{5}+\frac{3}{2}).\frac{1}{x}=\frac{1}{20} \) is established based on the premise that A and B, working collaboratively, can complete the task in 20 days.

The solution to this equation yields x=36.

Consequently, the faster individual (A) will complete the work independently in 36 days.

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