Question:medium

$50\, mL$ of $0.5\, M$ oxalic acid is needed to neutralize $25\, mL$ of sodium hydroxide solution. The amount of $NaOH$ in $50\, mL$ of the given sodium hydroxide solution is :

Updated On: Apr 3, 2026

40 g
20 g
80 g
4 g

Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?

Questions Asked in JEE Main exam

Consider the following compounds. Arrange these compounds in a n increasing order of reactivity with nitrating mixture. The correct order is :

JEE Main - 2026
Chemical Kinetics

View Solution

Let $ A, B, C $ be three $ 2\times2 $ matrices with real entries such that \[ B=(I+A)^{-1} \quad \text{and} \quad A+C=I. \] If \[ BC=\begin{bmatrix}1 & -5 \\-1 & 2\end{bmatrix} \quad \text{and} \quad B\begin{bmatrix}x_1\\x_2\end{bmatrix} =\begin{bmatrix}12\\-6\end{bmatrix}, \] then $ x_1+x_2 $ is:

JEE Main - 2026
Matrices and Determinants

View Solution

Six point charges are kept $60^\circ$ apart from each other on the circumference of a circle of radius $ R $ as shown in figure. The net electric field at the center of the circle is ___________. ($ \varepsilon_0 $ is permittivity of free space)

JEE Main - 2026
Electric Charge

View Solution

For the matrices $ A = \begin{bmatrix} 3 & -4 \\ 1 & -1 \end{bmatrix} $ and $ B = \begin{bmatrix} -29 & 49 \\ -13 & 18 \end{bmatrix} $, if $ (A^{15} + B) \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} 0\\ 0 \end{bmatrix} $, then among the following which one is true?}

JEE Main - 2026
Matrices

View Solution

$50\, mL$ of $0.5\, M$ oxalic acid is needed to neutralize $25\, mL$ of sodium hydroxide solution. The amount of $NaOH$ in $50\, mL$ of the given sodium hydroxide solution is :

The Correct Option is D

Solution and Explanation

Top Questions on Some basic concepts of chemistry

Questions Asked in JEE Main exam