Question:hard

20 labors engaged in a farm-operation on paddy farm for 6h. In an ideal conditions, how much maximum energy is utilized by labors into the farm?
(A)8.94 kWh
(B)120 kWh
(C)12 hPh
(D)240 hPh
Choose the correct answer from the options given below:

Show Hint

Take 0.1 hp per laborer, multiply by number of workers and hours, then convert hp-h to kWh to check which pair matches.
  • (A), and (C) only.
  • (B) and (D) only.
  • (C) and (D) only.
  • (B) and (C) only.
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Calculate the total man-power output first. With the standard value of 0.1 hp per laborer under ideal conditions, 20 laborers together give $20 \times 0.1 = 2$ hp of total power.
Step 2: Multiply by the working duration of 6 hours to get the energy consumed: $2 \times 6 = 12$ hp-h, which is exactly option (C).
Step 3: Check consistency by converting this same energy into kilowatt-hours using $1 \text{hp} = 0.746 \text{kW}$: $12 \times 0.746 \approx 8.94$ kWh, which is option (A). Since both values describe the identical amount of energy, only options (A) and (C) can be correct together; (B) at 120 kWh and (D) at 240 hp-h are roughly ten to twenty times too large to be right.
\[\boxed{\text{(A) and (C) only}}\]
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