Question

0.05 cm thick coating of silver is deposited on a plate of 0.05 m² area. The number of silver atoms deposited on plate are _____ × 10²³. (At mass Ag = 108,d = 7.9 g/cm³)

Answer 1

Correct Answer: 11

Step 1. Determine the volume of silver coating: \(Volume = 0.05 \times 0.05 \times 10000 = 25 \, \text{cm}^3\)

Step 2. Compute the mass of silver deposited: \(Mass\ of silver = 25 \times 7.9 \, \text{g}\)

Step 3. Calculate the moles of silver atoms: \(\text{Moles of silver } = \frac{25 \times 7.9}{108}\)

Step 4. Quantify the number of atoms: \(\text{Number of atoms} = \frac{25 \times 7.9}{108} \times 6.023 \times 10^{23} = 11.01 \times 10^{23}\)