List of top Physics Questions on de broglie hypothesis

Find the ratio of the de Broglie wavelengths of a proton and an alpha particle accelerated through the same potential difference.

Calculate the de-Broglie wavelength of an electron accelerated through a potential difference of $100\text{ V}$.

The de-Broglie wavelength of a moving bus with speed $ v $ is $ \lambda $. Some passengers left the bus at a stoppage. Now when the bus moves with twice of its initial speed, its kinetic energy is found to be twice its initial value. What is the de-Broglie wavelength of the bus now?

An electron accelerated by a potential difference '$V$' has de-Broglie wavelength '$\lambda$'. If the electron is accelerated by a potential difference '$9 \text{ V}$', its de-Broglie wavelength will be}

A proton accelerated through a potential difference of V volts has a de-Broglie wavelength $\lambda$ associated with it. In order to get the same wavelength associated with an $\alpha$-particle, the required accelerating potential is

The de-Broglie wavelength of a moving bus with speed $ v $ is $ \lambda $. Some passengers left the bus at a stop. Now, when the bus moves with twice of its initial speed, its kinetic energy is found to be twice of its initial value. What is the de-Broglie wavelength of the bus now?

A photon and an electron have the same energy $ E $. If $ \lambda_p $ is the wavelength of the photon and $ \lambda_e $ is the de Broglie wavelength of the electron, then the ratio $ \frac{\lambda_p}{\lambda_e} $ is:

The de-Broglie wavelength associated with a ball of mass 150 g traveling at 30.0 m/s would be

The de Broglie wavelength associated with an electron moving with energy 5 eV is:

The kinetic energy of an alpha particle is four times the kinetic energy of a proton. The ratio $ \left( \frac{\lambda_\alpha}{\lambda_p} \right) $ of de Broglie wavelengths associated with them will be:

If $ \lambda $ and $ K $ are de Broglie wavelength and kinetic energy, respectively, of a particle with constant mass. The correct graphical representation for the particle will be:

The wavelength of a photon is equal to the wavelength associated with an electron. Both will have the same value of:

Let $ \lambda_e, \lambda_p, \lambda_d $ be the wavelengths associated with an electron, a proton, and a deuteron, all moving with the same speed. Then the correct relation between them is:

De-Broglie wavelength of an electron orbiting in the $n = 2$ state of hydrogen atom is close to (Given Bohr radius = 0.052 nm):

A photon and an electron have the same energy $ E $. If $ \lambda_p $ is the wavelength of the photon and $ \lambda_e $ is the de Broglie wavelength of the electron, then the ratio $ \frac{\lambda_p}{\lambda_e} $ is:

Calculate the de Broglie wavelength of an electron moving with velocity $ 6 \times 10^6 \, m/s $. (Mass of electron $ m = 9.11 \times 10^{-31} \, kg $, Planck's constant $ h = 6.626 \times 10^{-34} \, Js $)

The de-Broglie wavelength of an electron is the same as that of a photon. If the velocity of the electron is 25% of the velocity of light, then the ratio of the K.E. of the electron to the K.E. of the photon will be:

De Broglie wavelength of proton = $λ$ and that of an a particle $2λ$. The ratio of velocity of proton to that of $\alpha$ particle is

A proton and an electron are associated with the same de-Broglie wavelength. The ratio of their kinetic energies is:
Given: $h = 6.63 \times 10^{-34} \, \text{Js}$, $m_e = 9.0 \times 10^{-31} \, \text{kg}$, and $m_p = 1836 \times m_e$

A proton and an electron have the same de Broglie wavelength. If $K_p$ and $K_e$ be the kinetic energies of proton and electron respectively. Then choose the correct relation:

A proton, an electron, and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as:

The de-Broglie wavelength associated with a particle of mass $ m $ and energy $ E $ is \[\lambda = \frac{h}{\sqrt{2mE}}.\]The dimensional formula for Planck's constant is:

The de Broglie wavelengths of a proton and an α particle are $ \lambda $ and $ 2\lambda $ respectively. The ratio of the velocities of proton and α particle will be:

Determine ratio of de broglie wavelength of $α- particle$ and proton of same kinetic energy is