If the function
\[
f(x)=
\begin{cases}
\dfrac{\sin x-\tan x}{x^{3}}, & -\dfrac{\pi}{2}[1ex]
a, & x=0,[1ex]
\dfrac{\sin (b-3)x+\sin bx}{\sin x}, & 0<x<\dfrac{\pi}{2},
\end{cases}
\]
is continuous in
\[
\left(-\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right),
\]
then \(a+2b=\)