Question:medium

The area of the region bounded by the curves \[ y=2^x,\qquad y^2=4x \] and the lines \[ x=\frac12,\qquad x=1 \] is

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When finding the area between two curves, \[ \boxed{ \text{Area} = \int_a^b (\text{Upper curve}-\text{Lower curve})\,dx. } \] Always determine which curve lies above the other before integrating.
Updated On: Jul 18, 2026
  • \(\dfrac{2-\sqrt2}{\log2}-\dfrac{4-\sqrt2}{3}\)
  • \(\dfrac{4-\sqrt2}{3}-\dfrac{2-\sqrt2}{\log2}\)
  • \(\dfrac{4+\sqrt2}{3}-\dfrac{2-\sqrt2}{\log2}\)
  • \(\dfrac{2-\sqrt2}{\log2}-\dfrac{4+\sqrt2}{3}\)
Show Solution

The Correct Option is B

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