Exams
Subjects
Classes
Home
Mathematics
List of top Mathematics Questions on Series
Let \[ S=\frac{1}{2!5!}+\frac{1}{3!2!3!}+\frac{1}{5!2!1!}+\cdots \text{ up to 13 terms}. \] If $13S=\dfrac{2^k}{n!}$, $k\in\mathbb{N}$, then $n+k$ is equal to
JEE Main - 2026
JEE Main
Mathematics
Series
The value of
$\lim_{n \to \infty} \sum_{k=1}^{n} \frac{k^3 + 6k^2 + 11k + 5}{(k+3)!}$ is:
JEE Main - 2025
JEE Main
Mathematics
Series
Given the series
$\frac{1}{1^4} + \frac{1}{2^4} + \frac{1}{3^4} + \cdots = \frac{\pi^4}{90},$
$\frac{1}{1^4} + \frac{1}{3^4} + \frac{1}{5^4} + \cdots = \alpha,$
$\frac{1}{2^4} + \frac{1}{4^4} + \frac{1}{6^4} + \cdots = \beta.$
Then find
$\frac{\alpha}{\beta}$
JEE Main - 2025
JEE Main
Mathematics
Series
If \[1 + \frac{\sqrt{3} - \sqrt{2}}{2\sqrt{3}} + \frac{5 - 2\sqrt{6}}{18} + \frac{9\sqrt{3} - 11\sqrt{2}}{36\sqrt{3}} + \frac{49 - 20\sqrt{6}}{180} + \cdots\] up to \(\infty = 2 \left( \sqrt{\frac{b}{a}} + 1 \right) \log_e \left( \frac{a}{b} \right)\), where \(a\) and \(b\) are integers with \(\gcd(a, b) = 1\), then (11a + 18b\) is equal to _________.
JEE Main - 2024
JEE Main
Mathematics
Series
The coefficient of \(x^n\) in the expansion of \[\frac{e^{7x} + e^x}{e^{3x}}\] is:
BITSAT - 2024
BITSAT
Mathematics
Series
The sum of the infinite series \(1 + \frac{5}{6} + \frac{12}{6^2} + \frac{22}{6^3} + \frac{35}{6^4} + \dots\) is equal to:
BITSAT - 2024
BITSAT
Mathematics
Series
If \( A = 1 + r^a + r^{2a} + r^{3a} + \dots \infty \) and \( B = 1 + r^b + r^{2b} + r^{3b} + \dots \infty \), then \( \frac{a}{b} \) is equal.
BITSAT - 2024
BITSAT
Mathematics
Series
There are four numbers of which the first three are in GP and the last three are in AP, whose common difference is 6. If the first and the last numbers are equal, then the two other numbers are:
BITSAT - 2024
BITSAT
Mathematics
Series
If \( \sum_{k=1}^{n} k(k+1)(k-1) = pn^4 + qn^3 + tn^2 + sn \), where \( p, q, t, s \) are constants, then the value of \( s \) is equal to:
BITSAT - 2024
BITSAT
Mathematics
Series
Let $S$ be the set of all values of $a_1$ for which the mean deviation about the mean of $100$ consecutive positive integers $a_1, a_2, a_3, \ldots , a_{100}$ is $25$ Then $S$ is
JEE Main - 2023
JEE Main
Mathematics
Series
The sum $\displaystyle\sum_{n=1}^{21} \frac{3}{(4 n-1)(4 n+3)}$ is equal to
JEE Main - 2023
JEE Main
Mathematics
Series
Let a
n
be the n
th
term of the series 5 + 8 + 14 + 23 + 35 + 50 +.... and Sn = \(\displaystyle\sum_{k=1}^{n} a_k.\) Then S
30
- a
40
is equal to
JEE Main - 2023
JEE Main
Mathematics
Series
If the sum of the series
\(\left(\frac{1}{2}-\frac{1}{3}\right) + \left(\frac{1}{2^2}-\frac{1}{2·3} + \frac{1}{3^2}\right) + \left(\frac{1}{2^2}-\frac{1}{2^2·3} + \frac{1}{2·3^2} - \frac{1}{3^3}\right) + \left(\frac{1}{2^4}-\frac{1}{2^3·3} + \frac{1}{2^2·3^2} - \frac{1}{2·3^3} + \frac{1}{3^4}\right) + ........ \)
is
\(\frac{α}{β}\)
, where α and β are co-prime, then α+3β is equal to ________
JEE Main - 2023
JEE Main
Mathematics
Series
If fraceˣ+e⁵xe³x=a₀+a₁x+a₂x²+a₃x³+⋯ then the value of 2a₁+2³a₃+2⁵a₅+⋯ is
BITSAT - 2019
BITSAT
Mathematics
Series
The sum to \( n \) terms of the series
\( \dfrac{1}{2} + \dfrac{3}{4} + \dfrac{7}{8} + \dfrac{15}{16} + \cdots \)
is
BITSAT - 2016
BITSAT
Mathematics
Series
\( \left(x + \dfrac{1}{x}\right)^2 + \left(x^2 + \dfrac{1}{x^2}\right)^2 + \cdots + \left(x^n + \dfrac{1}{x^n}\right)^2 \)
upto \( n \) terms is
BITSAT - 2016
BITSAT
Mathematics
Series
If \[ \frac{e^x+e^{5x}}{e^{3x}}=a_0+a_1x+a_2x^2+a_3x^3+\cdots, \] then the value of \(2a_1+2^3a_3+2^5a_5+\cdots\) is
BITSAT - 2015
BITSAT
Mathematics
Series
The sum of the series \[ 1 + 2^2 + 3^2 + 4^2 + \dots + 100^2 \] is
BITSAT - 2013
BITSAT
Mathematics
Series
The sum to $10$ terms of the series $\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\frac{3}{1+3^2+3^4}+\ldots $ is
JEE Main
Mathematics
Series