List of top Physics Questions on Projectile motion asked in KEAM

If a ball is thrown horizontally with a velocity of $10\text{ ms}^{-1}$ from the tower of height 45 m, then it strikes the ground at a distance of $(g=10\text{ ms}^{-2})$

The horizontal range of a projectile is maximum when the angle of projection is ____.

A cricketer hits a ball at $45^{\circ}$ with velocity $40\ \text{m s}^{-1}$ and it falls at $160\ \text{m}$. If he hits at the same angle with $50\ \text{m s}^{-1}$, the distance will be:

If \(\theta\) is the angle of projection of an object for which the horizontal range is equal to the maximum height attained, then the value of \(\tan \theta\) is

Two projectiles \(P\) and \(Q\) thrown with velocities \(v\) and \(\dfrac{v}{2}\) respectively have the same range. If \(Q\) is thrown at an angle of \(15^\circ\) to the horizontal, \(P\) must be thrown at an angle of

A ball falls from a table top with initial horizontal speed $V_0$. In the absence of air resistance, which of the following statement is correct

From the ground, a projectile is fired at an angle of $60^\circ$ to the horizontal with a speed of $20$ m/s. Take acceleration due to gravity as $10$ m/s$^2$. The horizontal range of the projectile is

A body is thrown up with a speed \( u \), at an angle of projection \( \theta \). If the speed of the projectile becomes \( \frac{u}{\sqrt{2}} \) on reaching the maximum height, the maximum vertical height attained by the projectile is

A cricket ball is hit at an angle of 30° to the horizontal with a kinetic energy E. Its kinetic energy when it reaches the highest point is

The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is

The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is

The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is