Question:medium
The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is
The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is
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Total velocity at maximum height is not zero—only the vertical component is. The projectile still moves forward with its constant horizontal velocity $u \cos\theta$.
Updated On: May 6, 2026
- $u \sin\theta$
- $u \cos\theta$
- $\frac{u}{\sin\theta}$
- 0
- $\frac{u}{\cos\theta}$
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The Correct Option is D
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