Question:medium
From the ground, a projectile is fired at an angle of $60^\circ$ to the horizontal with a speed of $20$ m/s. Take acceleration due to gravity as $10$ m/s$^2$. The horizontal range of the projectile is
From the ground, a projectile is fired at an angle of $60^\circ$ to the horizontal with a speed of $20$ m/s. Take acceleration due to gravity as $10$ m/s$^2$. The horizontal range of the projectile is
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Use identity $\sin(180^\circ - \theta) = \sin \theta$ to simplify projectile problems.
Updated On: May 1, 2026
- $10\sqrt{3}$ m
- $20$ m
- $20\sqrt{3}$ m
- $40\sqrt{3}$ m
- $400\sqrt{3}$ m
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The Correct Option is C
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