List of top Mathematics Questions on linear inequalities asked in KEAM

If $|2x-3|<5, x\in\mathbb{R}$, then $x$ lies in the interval

If $\frac{21x-6}{4}-9\le0$ and $\frac{x-1}{3}+1\ge0, x\in\mathbb{R}$ then $x$ lies in the interval

Let $x$ be a real number such that $\dfrac{x-3}{x-2} \geq 1$. Then the solution set of the inequality is:

The shaded region \(ABC\) shown in the diagram is given by the inequalities

The solution set of inequality \( |x+2|<3 \) is

If \(\frac{x+1}{x-1}<2\), then \(x\) lies in the interval

If \(x \neq 11\) satisfies the inequality \(\frac{2x - 21}{x - 11} \geq 3\), then \(x\) lies in the interval

If \( \frac{|x-3|}{x-3} > 0 \), then:

If \( |x-1| + |x-3| \leq 8 \), then the values of \( x \) lie in the interval:

The area and perimeter of a rectangle are \(A\) and \(P\) respectively. Then \(P\) and \(A\) satisfy the inequality

The shaded region shown in the figure is given by the inequations: [height=5cm]{Screenshot 2026-05-01 102102.png}

The shaded region shown in the figure is given by the inequations: [height=5cm]{Screenshot 2026-05-01 102102.png}

The shaded region shown in the figure is given by the inequations: [height=5cm]{Screenshot 2026-05-01 102102.png}