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The area and perimeter of a rectangle are \(A\) and \(P\) respectively. Then \(P\) and \(A\) satisfy the inequality
The area and perimeter of a rectangle are \(A\) and \(P\) respectively. Then \(P\) and \(A\) satisfy the inequality
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For rectangles, minimum perimeter for fixed area occurs when it becomes a square.
Updated On: May 8, 2026
- \( P + A > PA \)
- \( P^2 \le A \)
- \( A - P < 2 \)
- \( P^2 \le 4A \)
- \( P^2 \ge 16A \)
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The Correct Option is
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