Question:medium
Let $x$ be a real number such that $\dfrac{x-3}{x-2} \geq 1$. Then the solution set of the inequality is:
Let $x$ be a real number such that $\dfrac{x-3}{x-2} \geq 1$. Then the solution set of the inequality is:
Show Hint
Always simplify rational inequalities before applying sign analysis.
Updated On: Apr 24, 2026
- $(-\infty,3)$
- $(-\infty,2)$
- $[0,\infty)$
- $(-9,\infty)$
- $(0,8)$
Show Solution
The Correct Option is B
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