Question:medium

Xenon hexafluoride on partial hydrolysis produces compounds ?X? and ?Y?. Compounds ?X? and ?Y? and the oxidation state of Xe are respectively :

Updated On: Apr 1, 2026
  • $XeO_2(+4)$ and $XeO_3(+6)$
  • $XeOF_4(+6)$ and $XeO_3(+6)$
  • $XeO_2F_2(+6)$ and $XeO_2(+4)$
  • $XeOF4(+6)$ and $XeO2F2(+6)$
Show Solution

The Correct Option is D

Solution and Explanation

Xenon hexafluoride (XeF_6) is known to undergo hydrolysis reactions. The partial hydrolysis of xenon hexafluoride can be represented through the following reaction:

XeF_6 + H_2O \rightarrow XeOF_4 + 2HF

In the above reaction, xenon oxyfluoride (XeOF_4) is formed along with hydrogen fluoride (HF). Here, xenon exhibits an oxidation state of +6 in XeOF_4.

Further reaction with water can lead to the formation of the product XeO_2F_2 as shown below:

XeOF_4 + H_2O \rightarrow XeO_2F_2 + 2HF

In this compound (XeO_2F_2), xenon again has an oxidation state of +6.

Thus, the products of the partial hydrolysis of xenon hexafluoride are XeOF_4 and XeO_2F_2, both with xenon in the +6 oxidation state. This aligns with the given correct answer choice.

Conclusion: The correct option is XeOF_4(+6) and XeO_2F_2(+6).

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