Xenon hexafluoride (XeF_6) is known to undergo hydrolysis reactions. The partial hydrolysis of xenon hexafluoride can be represented through the following reaction:
XeF_6 + H_2O \rightarrow XeOF_4 + 2HF
In the above reaction, xenon oxyfluoride (XeOF_4) is formed along with hydrogen fluoride (HF). Here, xenon exhibits an oxidation state of +6 in XeOF_4.
Further reaction with water can lead to the formation of the product XeO_2F_2 as shown below:
XeOF_4 + H_2O \rightarrow XeO_2F_2 + 2HF
In this compound (XeO_2F_2), xenon again has an oxidation state of +6.
Thus, the products of the partial hydrolysis of xenon hexafluoride are XeOF_4 and XeO_2F_2, both with xenon in the +6 oxidation state. This aligns with the given correct answer choice.
Conclusion: The correct option is XeOF_4(+6) and XeO_2F_2(+6).
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 