Write the SI unit of cell constant.

Question

Consider following reaction :
$Fe(OH)_2 + 2e^- \rightarrow Fe(s) + 2OH^-$ , $E^{\circ} = -0.88 \text{ V}$
$AgBr(s) + e^- \rightarrow Ag(s) + Br^-(aq)$ , $E^{\circ} = 0.07 \text{ V}$
Select the correct statement.
(1) $E^{\circ}_{cell} = -0.95 \text{V}$
(2) $E^{\circ}_{cell}$ is an extensive property
(3) $Fe$ is getting reduced
(4) Net cell reaction: $Fe(s) + 2OH^-(aq) + 2AgBr(s) \rightarrow Fe(OH)_2 + 2Ag(s) + 2Br^-(aq)$

Answer 1

Step 1: Understanding the Concept:
Cell constant ($b$) is a characteristic property of a conductivity cell, defined as the ratio of the distance between electrodes to the cross-sectional area of the electrodes.
Step 2: Key Formula or Approach:
\[ \text{Cell constant } (b) = \frac{l}{a} \]
where $l$ is length and $a$ is area.
Step 3: Detailed Explanation:
The SI unit of length ($l$) is meters ($m$).
The SI unit of area ($a$) is square meters ($m^2$).
Units of cell constant = $\frac{m}{m^2} = m^{-1}$ (per meter).
While $cm^{-1}$ is frequently used in laboratories, the SI unit is $m^{-1}$.
Step 4: Final Answer:
The SI unit of cell constant is $m^{-1}$.

Write the SI unit of cell constant.

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Solution and Explanation

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