Question:medium

Write down the product compound for the following reaction:

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It doesn't matter if the side chain is Methyl, Ethyl, or Isobutyl; if it has a benzylic hydrogen, $KMnO_4$ turns it into a $-COOK$ (or $-COOH$ after acidification) group. Note: Tertiary butyl groups ($no$ benzylic H) will $not$ react this way!
Updated On: Oct 3, 2026
  • Phenylacetic acid salt (Potassium phenylacetate, \( C_6H_5CH_2COOK \))
  • Benzoic acid salt (Potassium benzoate, \( C_6H_5COOK \))
  • Phenyl acetone
  • Benzaldehyde
Show Solution

The Correct Option is B

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