Why phenol does not undergo protonation readily?
Phenol exhibits limited protonation due to the delocalization of the hydroxyl group's oxygen lone pair into the benzene ring via resonance. This resonance effect significantly reduces phenol's basicity relative to alcohols.
In phenol, the lone pair on the hydroxyl oxygen (\( -OH \)) is delocalized into the aromatic system. This electron density transfer to the benzene ring results in resonance structures such as: \[ \text{C}_6\text{H}_5\text{O} \rightleftharpoons \text{C}_6\text{H}_5\text{O}^- \] The consequence of this delocalization is a diminished electron density on the oxygen atom, thereby decreasing its affinity for accepting a proton (\( \text{H}^+ \)).
Consequently, the oxygen in phenol is less basic than that in alcohols. In alcohols, the oxygen's lone pair is not delocalized into an aromatic ring and remains more accessible for proton acceptance, rendering alcohols more basic than phenol.
The reduced electron density on phenol's oxygen atom makes it less prone to protonation. Conversely, alcohols, with their more available oxygen lone pairs, readily undergo protonation.
Phenol resists protonation due to resonance-induced electron withdrawal from the oxygen into the benzene ring, which lowers its basicity compared to alcohols.
Amides are less basic than amines.
Which is the correct order of acid strength from the following?