Answer:
The oxidising or reducing behaviour of a substance depends on the oxidation state of the central atom and whether it can both increase or decrease its oxidation state.
Sulphur dioxide (SO2) and hydrogen peroxide (H2O2):
In sulphur dioxide, sulphur is in an intermediate oxidation state of +4. Hence, sulphur can either be oxidised to a higher oxidation state (+6) or reduced to a lower oxidation state (0 or −2). Therefore, SO2 can act both as an oxidising agent and a reducing agent.
In hydrogen peroxide, oxygen is in an oxidation state of −1, which is also an intermediate value. Thus, oxygen can be oxidised to 0 (in O2) or reduced to −2 (in H2O). Hence, H2O2 shows both oxidising and reducing properties.
Ozone (O3) and nitric acid (HNO3):
In ozone, oxygen effectively acts as a strong oxidising species and readily decomposes to give O2, releasing nascent oxygen. It does not undergo further oxidation and therefore acts only as an oxidising agent.
In nitric acid, nitrogen is already present in its highest oxidation state of +5. Since nitrogen cannot increase its oxidation state further, HNO3 cannot act as a reducing agent and thus behaves only as an oxidising agent.
Conclusion:
SO2 and H2O2 act as both oxidising and reducing agents because their central atoms are in intermediate oxidation states, whereas O3 and HNO3 act only as oxidising agents because their atoms are either highly oxidising or already in the maximum oxidation state.
The products formed in the following reaction, A and B, are:
