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The products formed in the following reaction, A and B, are: 

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Tollens' reagent oxidizes aldehydes to carboxylic acids, while sodium borohydride reduces ketones and aldehydes to alcohols.
Updated On: Jan 13, 2026
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The Correct Option is C

Solution and Explanation

The reaction occurs in two distinct phases:

Phase 1: Oxidation Utilizing Tollens' Reagent

  • Tollens' reagent, comprising \([Ag(NH_3)_2]^+ \) and \( OH^- \), specifically oxidizes aldehydes to carboxylic acids.
  • Within this reaction, the aldehyde moiety (\(-CHO\)) of the substance is oxidized, yielding a carboxylic acid group (\(-COOH\)).
  • The resultant compound, designated as \( A \), following oxidation, is: \[ \text{A} = \text{Substance featuring an aldehyde group oxidized to a carboxylic acid: } \text{HCOOH}. \]

Phase 2: Reduction Employing Sodium Borohydride

  • Sodium borohydride (\( NaBH_4 \)) acts as a selective reducing agent, converting aldehydes and ketones into their respective alcohols.
  • In the specific compound provided, the ketone functional group (\(-C=O\)) is reduced to a secondary alcohol (\(-CH(OH)-\)).
  • The resulting compound, labeled \( B \), after reduction is: \[ \text{B} = \text{Substance with the ketone group reduced to an alcohol: } \text{HCOOH}. \]

Concluding Statement: Compounds \( A \) and \( B \) align with:

\[ \boxed{\text{Option C}} \]

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