Question:medium

Which one of the following is not formed when acetone reacts with 2-pentanone in the presence of dilute NaOH followed by heating?

Updated On: May 30, 2026
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This is a Cross-Aldol condensation reaction between two different ketones: Acetone (\(CH_{3}COCH_{3}\)) and 2-Pentanone (\(CH_{3}COCH_{2}CH_{2}CH_{3}\)).
Each ketone can form enolates from its \(\alpha\)-hydrogens and attack the carbonyl carbon of either itself or the other ketone.
Detailed Explanation:
Acetone has one type of \(\alpha\)-hydrogen.
2-Pentanone has two types of \(\alpha\)-hydrogens: the methyl group (\(C1\)) and the methylene group (\(C3\)).
This leads to a mixture of four cross-condensation products and multiple self-condensation products.
Structure (2) depicts a molecule that cannot be generated by any combination of these precursors through the standard Aldol mechanism (nucleophilic attack of \(\alpha\)-carbon on a carbonyl carbon followed by dehydration).
The specific chain length and substitution pattern in Structure (2) do not correspond to the possible fragments of acetone (3C) and 2-pentanone (5C).
Step 2: Final Answer:
Structure (2) is not a possible product of this specific cross-aldol condensation.
Was this answer helpful?
3