de-Broglie's wavelength is given by \(λ=\frac {h}{mv}\), where \(m\) = mass of the particle, \(v\) = group velocity of the particle
The uncertainty principle is \(△E × △t ≥ \frac {h}{4\pi}\)
Half-filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry and more balanced arrangement
The energy of 2s orbital is less than the energy of 2p orbital in case of Hydrogen like atoms
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The Correct Option isD
Solution and Explanation
Let's evaluate each statement to determine which one is incorrect:
De-Broglie's wavelength is given by \(λ=\frac {h}{mv}\), where \(m\) = mass of the particle, \(v\) = group velocity of the particle: This statement is correct. According to de Broglie's hypothesis, particles like electrons exhibit wave-like properties, and the wavelength \(λ\) is given by the formula \(λ=\frac {h}{mv}\).
The uncertainty principle is \(△E × △t ≥ \frac {h}{4\pi}\): This statement is accurate. According to Heisenberg's uncertainty principle, the product of uncertainty in energy and time is greater than or equal to \(\frac {h}{4\pi}\).
Half-filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry, and more balanced arrangement: This statement is correct as well. In atomic chemistry, the stability of electron configurations is enhanced in half-filled and fully-filled orbitals due to exchange energy and symmetry.
The energy of 2s orbital is less than the energy of 2p orbital in case of Hydrogen like atoms: This statement is incorrect. For hydrogen-like atoms, which are one-electron systems, the energy of an orbital depends only on the principal quantum number \(n\). Therefore, 2s and 2p orbitals have the same energy in hydrogen-like atoms.
Thus, the incorrect statement is: The energy of 2s orbital is less than the energy of 2p orbital in case of Hydrogen like atoms.
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