Step 1: Meaning of negative deviation from Raoult's law.
Negative deviation from Raoult's law tab hota hai jab unlike molecules ke beech attraction, like molecules ke beech attraction se stronger hota hai. Is wajah se solution ke molecules vapour phase me easily escape nahi kar pate, aur vapour pressure expected value se kam ho jata hai.
Step 2: Identify the type of intermolecular interaction.
Chloroform \(\mathrm{CHCl_3}\) aur acetone \(\mathrm{CH_3COCH_3}\) ke mixture me strong intermolecular hydrogen bonding type interaction develop hota hai. Chloroform ka acidic hydrogen acetone ke carbonyl oxygen ke saath strong attraction show karta hai. Yeh unlike molecules ke beech attraction ko kaafi strong bana deta hai.
Step 3: Analysis of the given options.
(A) Chloroform + Acetone: Correct. Inke beech strong specific interaction hoti hai, isliye yeh negative deviation show karta hai.
(B) Benzene + Toluene: Incorrect. Dono ka nature similar hai, isliye yeh लगभग ideal solution ki tarah behave karte hain.
(C) Ethanol + Acetone: Incorrect in this context. Yeh standard textbook example nahi hai negative deviation ka.
(D) Bromoethane + Chloroethane: Incorrect. Inka behaviour bhi near-ideal hota hai because intermolecular forces kaafi similar hote hain.
Step 4: Conclusion.
Isliye jo solution negative deviation from Raoult's law show karega, woh chloroform aur acetone ka mixture hai.
Final Answer:Chloroform + Acetone.