Question:medium

Which of the following solutions will have a maximum boiling point?

Show Hint

Boiling point rises with \(i\times\) molality. For equal mass %, compare \(i/M\); the smallest-mass strong electrolyte wins.
Updated On: Jul 10, 2026
  • 1% glucose in water
  • 1% \(CaCl_2\) in water
  • 1% sucrose in water
  • 1% NaCl in water
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Rule. The more solute particles per unit mass of water, the higher the boiling point, because \(\Delta T_b\) tracks the total particle concentration.
Step 2: Count particles from 1 g of each solute. Particles \(= (1/M)\times i\).
Glucose: \((1/180)\times1 = 0.0056\) mol
Sucrose: \((1/342)\times1 = 0.0029\) mol
\(CaCl_2\): \((1/111)\times3 = 0.027\) mol
NaCl: \((1/58.5)\times2 = 0.0342\) mol
Step 3: Interpret. Strong electrolytes ionise fully, so NaCl and \(CaCl_2\) beat the sugars at once. Between the two salts, NaCl's very small formula mass (58.5) outweighs the extra ion of \(CaCl_2\).
Step 4: Conclusion. NaCl releases the most particles per gram, so its solution boils at the highest temperature.
\[\boxed{\text{NaCl}}\]
Was this answer helpful?
0