Question

Which of the following sets of quantum numbers is impossible arrangement?

• A. $n = 3, m = -2, s = +\frac{1}{2}$
• B. $n = 4, m = 3, s = +\frac{1}{2}$
• C. $n = 5, m = 2, s = -\frac{1}{2}$
• D. $n = 3, m = -3, s = -\frac{1}{2}$

Hint:

$m$ ranges from $-l$ to $+l$, and $l$ ranges from $0$ to $n-1$.

Answer 1

The Correct Option is D

Step 1: Conceptual Understanding:
$m$ ranges from $-l$ to $+l$, and $l$ ranges from $0$ to $n-1$.
Step 2: Explanation in Detail:
For $n=3$, possible $m$ values are $-2,-1,0,1,2$. $m = -3$ is not possible.
Step 3: Therefore, Stating the Final Answer
The set with $n=3, m=-3$ is impossible.