Which of the following reagents is used to distinguish ethers from hydrocarbons?
Show Hint
- \(\text{NaOH}\)
- \(\text{KMnO}_{4}\)
- Cold dilute \(\text{H}_{2}\text{SO}_{4}\)
- Cold concentrated \(\text{H}_{2}\text{SO}_{4}\)
The Correct Option is D
Solution and Explanation
NaOH has no reaction with ethers or alkanes.
Cold dilute acid is too weak to protonate an ether.
$\text{KMnO}_4$ does not react with either under cold conditions.
Step 2: Remaining option
Only cold concentrated $\text{H}_2\text{SO}_4$ dissolves the ether through oxonium salt formation.
Step 3: Conclusion
So option (D) is correct.
Final Answer:
The ether dissolves in cold concentrated sulphuric acid while the hydrocarbon does not. \[ \boxed{\text{(D) }\text{Cold concentrated }\text{H}_{2}\text{SO}_{4}} \]
Top Questions on Ethers
IUPAC name of the given ether is:
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Replacement of a hydrogen atom in a hydrocarbon by an alkoxy or carboxyl group yields a class of compounds known as ethers. Ethers are classified as symmetrical or unsymmetrical on the basis of groups attached to the oxygen atoms. Diethyl ether, a symmetrical ether, has been widely used as an inhalation anesthetic. Ethers can be prepared by acid catalyzed intermolecular dehydration of alcohols and Williamson's synthesis. Acid catalyzed dehydration of alcohols is not generally preferred as it gives a mixture of elimination and substitution products. In Williamson's synthesis, an alkyl halide is allowed to react with sodium alkoxide. Ethers containing substituted Alkyl groups may also be prepared by this method. The C-O bond in ether is weakly polar and is cleaved under drastic conditions with excess of hydrogen halides. In electrophilic substitution, the alkoxy group deactivates the aromatic ring and directs the incoming group to ortho and para positions.
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(A) Br\(_2\)/FeBr\(_3\)
(B) Mg, dry Ether
(C) CO\(_2\), H\(_3\)O\(^+\)
(D) Methanol, Conc. H\(_2\)SO\(_4\) - What happens when C₆H₅–O–R is treated with HX?
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