Step 1: Think about the products
To get the same product from an aldehyde and a ketone, the carbonyl must lose its oxygen completely.
Step 2: Pick the full reduction
Only Clemmensen reduction (Zn-Hg, conc. HCl) turns C=O into $\text{CH}_{2}$.
Step 3: Check the rest
The other reagents give alcohols, which are different: propan-1-ol versus propan-2-ol.
Final Answer:
Only Zn-Hg/conc. HCl removes the oxygen and gives propane in both cases.
\[ \boxed{\text{(D) }\text{Zn-Hg / Conc HCl}} \]