Question

Which of the following molecules represents the order of hybridisation $sp^2 , sp^2, sp, sp$ from left to right atoms ?

• A. $CH3 -C H = CH -CH3$
• B. $HC \equiv C - C \equiv CH$
• C. $CH_2 = CH - CH = CH_2$
• D. $CH_2 = CH - C \equiv CH $

Answer 1

The Correct Option is D

To determine the correct molecule based on the given hybridization order, let's analyze the hybridization states of the carbon atoms in each option. We're looking for a sequence of hybridizations: sp^2, sp^2, sp, sp.

Explanation of Hybridization:

• Carbon atoms are sp^2 hybridized when they form a double bond and are bonded to three groups, including σ bonds.
• Carbon atoms are sp hybridized when they form triple bonds or two double bonds, as they are bonded to two groups only.

Analyze Each Option:

1. CH_3 - CH = CH - CH_3:
   • The first and last carbon atoms are sp^3 hybridized (single bonds).
   • The middle carbon atoms are sp^2 hybridized (double bonded).
   • This option does not match the required sequence.
2. HC \equiv C - C \equiv CH:
   • All carbon atoms are sp hybridized (each forms a triple bond).
   • This option does not match the required sequence.
3. CH_2 = CH - CH = CH_2:
   • All carbon atoms are sp^2 hybridized (each forms a double bond).
   • This option does not match the required sequence.
4. CH_2 = CH - C \equiv CH:
   • The first carbon of CH_2 is sp^2 hybridized.
   • The second carbon of CH is sp^2 hybridized.
   • The third carbon of C is sp hybridized (triple bond formation).
   • The fourth carbon of CH is sp hybridized (triple bond).
   • This option matches the required sequence of sp^2, sp^2, sp, sp.

Therefore, the correct answer is: CH_2 = CH - C \equiv CH.