Question:medium

Which of the following is true in respect of a zero order reaction?

Show Hint

In zero-order, rate is constant and independent of concentration.
Updated On: May 10, 2026
  • Plot of [Reactant] against time is a straight line with slope equal to k
  • Plot of [Reactant] against time is a straight line with slope equal to -k
  • Plot of [Reactant] against time is a straight line with slope equal to 2.303 k
  • Plot of [Reactant] against time is a straight line with slope equal to -2.303 k
  • Plot of [Reactant] against time is a straight line with slope equal to -k/2.303
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This question asks about the integrated rate law for a zero-order reaction and its graphical representation. We need to know the relationship between reactant concentration and time for a zero-order process.
Step 2: Key Formula or Approach:
The rate law for a zero-order reaction (A \( \rightarrow \) Products) is: \[ \text{Rate} = -\frac{d[A]}{dt} = k[A]^0 = k \] where [A] is the concentration of the reactant and k is the rate constant. To find the relationship between concentration and time, we need to integrate this rate law. \[ -\frac{d[A]}{dt} = k \implies d[A] = -k \, dt \] Integrating both sides from time \( t=0 \) (concentration \( [A]_0 \)) to time t (concentration \( [A]_t \)): \[ \int_{[A]_0}^{[A]_t} d[A] = \int_0^t -k \, dt \] \[ [A]_t - [A]_0 = -kt \] Rearranging this gives the integrated rate law: \[ [A]_t = -kt + [A]_0 \] Step 3: Detailed Explanation:
The integrated rate law for a zero-order reaction is: \[ [A]_t = -kt + [A]_0 \] This equation is in the form of a straight line, \( y = mx + c \), where: - \( y = [A]_t \) (the concentration of the reactant at time t) - \( x = t \) (time) - \( m = -k \) (the slope of the line) - \( c = [A]_0 \) (the y-intercept, which is the initial concentration) Therefore, a plot of the reactant concentration ([Reactant]) on the y-axis against time (t) on the x-axis will be a straight line with a slope equal to \( -k \).
Step 4: Final Answer:
The correct statement is that a plot of [Reactant] against time is a straight line with a slope equal to -k.
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