Which of the following is the correct order of acidic strength for the following compounds: HNO\(_3\), HClO\(_4\), and HClO\(_3\)?

Question

Let \(y=y(x)\) be the solution of the differential equation \[ x\frac{dy}{dx}=y-x^2\cot x,\quad x\in(0,\pi) \] If \(y\!\left(\frac{\pi}{2}\right)=\frac{\pi^2}{2}\), then \[ 6y\!\left(\frac{\pi}{6}\right)-8y\!\left(\frac{\pi}{4}\right) \] is equal to:

Answer 1

The strength of oxyacids, such as HNO₃, HClO₄, and HClO₃, is determined by the central atom's electronegativity and the number of attached oxygen atoms. An increased number of oxygen atoms and a higher electronegativity of the central atom result in a stronger acid.

HClO₄ exhibits the greatest acidity, attributed to chlorine's high electronegativity and the maximum number of bonded oxygen atoms.
HNO₃ surpasses HClO₃ in acidity due to nitrogen's greater electronegativity compared to chlorine and the presence of more oxygen atoms in nitric acid than in chlorous acid.

Which of the following is the correct order of acidic strength for the following compounds: HNO\(_3\), HClO\(_4\), and HClO\(_3\)?

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The Correct Option is A

Solution and Explanation

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