The sum of all the elements in the range of
\[
f(x)=\operatorname{sgn}(\sin x)+\operatorname{sgn}(\cos x)
+\operatorname{sgn}(\tan x)+\operatorname{sgn}(\cot x),
\]
where
\[
x\neq \frac{n\pi}{2},\ n\in\mathbb{Z},
\]
and
\[
\operatorname{sgn}(t)=
\begin{cases}
1, & t>0 \\
-1, & t<0
\end{cases}
\]
is:
Show Hint
For sign-function problems involving trigonometric expressions, quadrant-wise analysis is the fastest and most reliable method.
To solve this problem, we need to evaluate the function \(f(x) = \operatorname{sgn}(\sin x) + \operatorname{sgn}(\cos x) + \operatorname{sgn}(\tan x) + \operatorname{sgn}(\cot x)\) for all permissible values of \(x\) where \(x \neq \frac{n\pi}{2}\), \(n \in \mathbb{Z}\). Here's a step-by-step analysis:
First, consider the function \(\operatorname{sgn}(t)\) which is defined as:
\(\operatorname{sgn}(t) = 1\)
if \(t > 0\)
\(\operatorname{sgn}(t) = -1\)
if \(t < 0\)
Evaluate the sign of each trigonometric function within specific intervals because the sign depends on the quadrant of the angle:
For \(0 < x < \frac{\pi}{2}\) (First Quadrant):
\(\sin x > 0\), \(\cos x > 0\), \(\tan x > 0\), \(\cot x > 0\)