Step 1: Pin down primary amine.
A primary ($1^\circ$) amine has nitrogen carrying exactly one carbon group and a free $-NH_2$ with two hydrogens.
Step 2: Build a one line test.
Count carbons directly on nitrogen. One carbon means primary, two means secondary, three means tertiary.
Step 3: Check N-methyl aniline.
Structure $C_6H_5-NH-CH_3$ has both a phenyl and a methyl on nitrogen, so two carbons, that is secondary, reject.
Step 4: Check N-phenylbenzenamine.
This is diphenylamine $(C_6H_5)_2NH$ with two phenyl groups on nitrogen, again secondary, reject.
Step 5: Check methyl phenylamine.
This is just another name for N-methylaniline, two carbons on nitrogen, secondary, reject.
Step 6: Check isopropyl amine and conclude.
Structure $(CH_3)_2CH-NH_2$ has only one carbon group on nitrogen and an intact $-NH_2$, so it is primary.
\[ \boxed{\text{Isopropyl amine (option D)}} \]