Step 1: Analyze Mechanism of Each Option:
\begin{itemize}
\item
(A) Nucleophilic Addition:
Reaction of Acetaldehyde with HCN. The nucleophile (\(\text{CN}^-\)) attacks the electrophilic carbonyl carbon.
\[ \text{CH}_3\text{-C(=O)H} \xrightarrow{\text{CN}^-} \text{CH}_3\text{-CH(O}^-\text{)-CN} \xrightarrow{\text{H}^+} \text{CH}_3\text{-CH(OH)-CN} \]
\item (B) Nucleophilic Substitution (\(\text{S}_{\text{N}}1\)):
Hydrolysis of tertiary butyl halide. The nucleophile (\(\text{H}_2\text{O}\)) substitutes the leaving group (Halide \(\text{X}^-\)).
\item (C) Electrophilic Aromatic Substitution:
This is Friedel-Crafts Acylation.
The Lewis acid catalyst (\(\text{AlCl}_3\)) reacts with acetyl chloride to generate an electrophile (Acylium ion, \(\text{CH}_3\text{-C}^+\text{=O}\)).
\[ \text{CH}_3\text{COCl} + \text{AlCl}_3 \rightarrow \text{CH}_3\text{C}^+\text{O} + \text{AlCl}_4^- \]
This electrophile attacks the electron-rich benzene ring, substituting a hydrogen atom.
\[ \text{C}_6\text{H}_6 + \text{E}^+ \rightarrow \text{C}_6\text{H}_5\text{E} + \text{H}^+ \]
This matches the definition of electrophilic substitution.
\item (D) Elimination:
Reaction of vicinal dihalide with Zinc dust. It removes two bromine atoms to form a double bond (Debromination). This is an elimination reaction.
\end{itemize}
Required Answer: The reaction in option (C) is an electrophilic substitution.