Step 1: The test for an aldehyde is the presence of the terminal –CHO functional group (a hydrogen directly on the carbonyl carbon).
Step 2: Scan the structures for an H on the C=O carbon. Only CH3–CO–H shows the pattern R–CO–H, where R = CH3 and one bond is to hydrogen.
Step 3: The remaining three species have the carbonyl carbon sandwiched between two alkyl groups (R–CO–R'), the signature of a ketone.
Step 4: Therefore the aldehyde is \[ \boxed{CH_3CHO} \] i.e. option (i).