Question:medium

Which of the following is a correct statement for a thermodynamic system?

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Remember the main state functions in thermodynamics: Pressure (P), Volume (V), Temperature (T), Internal Energy (U), Enthalpy (H), Entropy (S), and Gibbs Free Energy (G). The two main path functions are Heat (q) and Work (w).
Updated On: Apr 28, 2026
  • The internal energy changes in all processes
  • Internal energy and entropy are state functions
  • Work is a state function
  • The work done in an adiabatic process is always zero
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Thermodynamic properties are strictly classified as either state functions (independent of the path taken) or path functions (dependent on the specific sequence of steps).
Step 2: Key Formula or Approach:
Analyze each statement against fundamental thermodynamic definitions, such as conditions for isothermal/adiabatic processes, and identify state vs. path variables.
Step 3: Detailed Explanation:
(A) In an isothermal process involving an ideal gas, temperature remains constant. Since the internal energy ($U$) of an ideal gas depends solely on temperature, internal energy does {not} change ($\Delta U = 0$). Therefore, it doesn't change in all processes. (Incorrect)
(B) Internal energy ($U$) and Entropy ($S$) depend exclusively on the current equilibrium state of the system (characterized by P, V, T), not on how that state was reached. They are state functions. (Correct)
(C) Work ($w$) and Heat ($q$) are heavily dependent on the specific path (e.g., reversible vs. irreversible expansion). They are path functions, not state functions. (Incorrect)
(D) In an adiabatic process, heat exchange is zero ($q = 0$). According to the First Law ($\Delta U = q + w$), the change in internal energy equals the work done ($\Delta U = w_{ad}$). Work is not zero unless it's free expansion. (Incorrect)
Step 4: Final Answer:
Statement (B) is the correct statement.
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