Question:medium

Which of the following are isoelectronic species i.e., those having the same number of electrons?
\(Na^+, K^+, Mg^{2+}, Ca^{2+}, S^{2–}, Ar\)

Updated On: Jan 20, 2026
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Solution and Explanation

Isoelectronic species are atoms or ions having the same number of electrons.

Step 1: Number of electrons in each

  • Na (Z = 11): Na+ has \(11 - 1 = 10\) electrons.
  • Mg (Z = 12): Mg2+ has \(12 - 2 = 10\) electrons.
  • K (Z = 19): K+ has \(19 - 1 = 18\) electrons.
  • Ca (Z = 20): Ca2+ has \(20 - 2 = 18\) electrons.
  • S (Z = 16): S2− has \(16 + 2 = 18\) electrons.
  • Ar (Z = 18): Ar has \(18\) electrons.

Step 2: Grouping isoelectronic species

  • Na+ and Mg2+ each have 10 electrons → they are isoelectronic with each other.
  • K+, Ca2+, S2− and Ar each have 18 electrons → they form another isoelectronic set.

Answer

The isoelectronic species are:

  • Na+ and Mg2+ (10 electrons each)
  • K+, Ca2+, S2− and Ar (18 electrons each)
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