Question:medium

Which linkage joins the monosaccharide units in sucrose?

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Sucrose consists of \(\alpha\)-D-glucose and \(\beta\)-D-fructose joined by a \(C_1-C_2\) glycosidic bond. Since both anomeric carbons participate in bonding, sucrose is a non-reducing sugar.
Updated On: May 1, 2026
  • \(C_1 - C_4\) glycosidic linkage
  • \(C_1 - C_2\) glycosidic linkage
  • \(C_1 - C_6\) glycosidic linkage
  • \(C_2 - C_4\) glycosidic linkage
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
Sucrose is a disaccharide (table sugar). We need to identify the specific carbons involved in the bond between its component sugar molecules.
Step 2: Detailed Explanation:
Sucrose is formed by the condensation of two monosaccharides:
1. \( \alpha \)-D-glucose
2. \( \beta \)-D-fructose
The linkage is formed between the anomeric carbon \( C_1 \) of the glucose molecule and the anomeric carbon \( C_2 \) of the fructose molecule.
Because both anomeric carbons are involved in the glycosidic bond, sucrose does not have a free aldehyde or ketone group.
This makes sucrose a non-reducing sugar.
Step 3: Final Answer:
The monosaccharide units in sucrose are joined by a \( C_1 - C_2 \) glycosidic linkage.
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