Question:medium

Which is the correct order for a given number \(\alpha\) in increasing order?

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For \(\alpha>1\), larger base → smaller logarithm. Bases: \(2<e<3<10\) \(\rightarrow\) logs: \(\log_{10}<\log_3<\log_e<\log_2\).

Updated On: Apr 7, 2026

\(\log_2 \alpha, \log_3 \alpha, \log_e \alpha, \log_{10} \alpha\)
\(\log_{10} \alpha, \log_3 \alpha, \log_e \alpha, \log_2 \alpha\)
\(\log_{10} \alpha, \log_e \alpha, \log_2 \alpha, \log_3 \alpha\)
None of the above

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The Correct Option is B

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Questions Asked in MET exam

If \(f(x) = \begin{cases} x, & 0 \le x \le 1 \\ 2x - 1, & 1<x \end{cases}\), then

MET - 2019
Continuity

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