Question

Which carbon atoms of $\alpha - D$ glucose and $\beta - D$ fructose respectively forms glycosidic linkage in sucrose?

• A. C — 1 and C — 2
• B. C-2 and C-1
• C. C-2 and C-6
• D. C-1 and C-5

Hint:

Sucrose involves the anomeric carbons of both sugars, which is why it is a non-reducing sugar.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Sucrose is a non-reducing sugar because its glycosidic bond ties up the anomeric carbons of both constituent monosaccharides.
Step 2: Key Formula or Approach:
Anomeric carbon of glucose is C1. Anomeric carbon of fructose is C2.
Step 3: Detailed Explanation:
In sucrose, \(\alpha\)-D-glucose is joined to \(\beta\)-D-fructose. The glycosidic linkage occurs between the C1 hydroxyl group of the glucose unit and the C2 hydroxyl group of the fructose unit. This \((1 \to 2)\) linkage removes their ability to act as reducing sugars.
Step 4: Final Answer:
The linkage involves C-1 of glucose and C-2 of fructose.