Step 1: We want a full 4d shell.
A completely filled 4d means $4d^{10}$. So we check the four elements.
Step 2: Check the configurations.
Sc has no 4d electrons. Zr is $[Kr]4d^2 5s^2$, only partly filled. Ag is $[Kr]4d^{10}5s^1$. Cd is $[Kr]4d^{10}5s^2$.
Step 3: Pick the stable one.
Cadmium ends the 4d series with a filled 4d and a filled 5s, a neat closed shell. So it is the clear choice.
\[ \boxed{\text{Cd, option 2}} \]