Question

\( E^0 \) value of Cu\(^{2+}\)/Cu is \( +0.34 \) V.

Hint:

- High atomization enthalpy and low hydration enthalpy make Cu\(^{2+} \rightarrow\) Cu less favorable, giving a positive \( E^0 \) value.

Answer 1

Step 1: Factors Influencing \( E^0 \) - The standard electrode potential (\( E^0 \)) is determined by: - Atomization Enthalpy (\( \Delta H^0_{\text{atom}} \)): Converting solid Cu to Cu\(^{2+}\) requires significant energy. - Hydration Enthalpy (\( \Delta H^0_{\text{hydr}} \)): Cu\(^{2+}\) exhibits low hydration energy, leading to reduced stability in aqueous environments.

Step 2: Impact on \( E^0 \) - The low hydration enthalpy disfavors the reduction of Cu\(^{2+}\) to Cu. - Consequently, the \( E^0 \) for Cu\(^{2+}/\)Cu is \( +0.34 \) V, signifying that copper is less reactive than typically anticipated.