When three identical bulbs of 60 watt 200 volt rating are connected in series to a 200-volt supply, the power drawn by them will be

Question

A charge of 2 $\mu C$ is placed in an electric field of intensity $ 4 \times 10^3 \, \text{N/C} $. What is the force experienced by the charge?

Answer 1

To determine the power drawn by three identical 60-watt, 200-volt bulbs connected in series to a 200-volt supply, we need to understand the concept of resistance and power in electrical circuits.

Firstly, let's calculate the resistance of one bulb using the formula P = V^2/R, where P is the power, V is the voltage, and R is the resistance.

For a 60-watt, 200-volt bulb:

R = V^2/P = (200)^2/60 = 40000/60 = 666.67 \, \Omega

The resistance of one bulb is approximately 666.67 \, \Omega.

Now, when three bulbs are connected in series, the total resistance R_{\text{total}} is the sum of the individual resistances:

R_{\text{total}} = 3 \times 666.67 = 2000 \, \Omega

The total resistance of the three bulbs in series is 2000 \, \Omega.

Next, we use Ohm's Law to find the current I flowing through the circuit using the total resistance:

I = V_{\text{total}}/R_{\text{total}} = 200/2000 = 0.1 \, \text{A}

The current flowing through the circuit is 0.1 \, \text{A}.

Finally, the power drawn by the entire series circuit can be calculated using the formula P = I^2 \times R_{\text{total}}:

P = (0.1)^2 \times 2000 = 0.01 \times 2000 = 20 \, \text{watts}

Therefore, the power drawn by the three bulbs connected in series is 20 watts.

This matches with the given correct answer: 20 watt.

Answer 2