Question:medium

When salt BA is treated with Conc. H\(_2\)SO\(_4\), reddish brown gas is liberated. The aqueous solution of BA gives pale yellow precipitate with AgNO\(_3\) solution. Which of the following anion(A) is present in the salt BA?

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Remember the colors of silver halide precipitates for qualitative analysis:
  • \textbf{AgCl}: White
  • \textbf{AgBr}: Pale Yellow (Cream)
  • \textbf{AgI}: Bright Yellow
Also, remember the key confirmatory tests for anions with concentrated H\(_2\)SO\(_4\). The reddish-brown gas (Br\(_2\)) is a classic indicator for bromide.
Updated On: Apr 28, 2026
  • Cl\(^-\)
  • CO\(_3\)\(^{2-}\)
  • SO\(_4\)\(^{2-}\)
  • Br\(^-\)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
This problem pertains to the systematic qualitative analysis of inorganic salts, specifically identifying anions based on their reaction with concentrated acid and silver nitrate.
Step 2: Key Formula or Approach:
Correlate the physical observations (reddish-brown gas with Conc. $H_2SO_4$ and pale yellow precipitate with $AgNO_3$) to the standard confirmatory tests for halide ions.
Step 3: Detailed Explanation:
1. Reaction with Conc. $H_{2SO_{4}$:} Bromide salts react with concentrated sulphuric acid to liberate hydrogen bromide ($HBr$), which is subsequently oxidized by the acid to bromine gas ($Br_{2}$). Bromine is a reddish-brown gas.
Reaction: $2NaBr + 2H_{2}SO_{4} \rightarrow Na_{2}SO_{4} + Br_{2} \uparrow + SO_{2} + 2H_{2}O$.
(Note: Nitrates also give brown gas $NO_2$, but the next test differentiates it).

2. Reaction with $AgNO_{3$:} Aqueous solution of bromide ions reacts with silver nitrate to form Silver Bromide ($AgBr$), which is a pale yellow precipitate. This precipitate is partially soluble in dilute aqueous ammonia but soluble in concentrated ammonia.
Reaction: $Br^{-} + Ag^{+} \rightarrow AgBr \downarrow$ (pale yellow).
In contrast, $Cl^-$ gives a white ppt ($AgCl$), and $I^-$ gives a bright yellow ppt ($AgI$).
Step 4: Final Answer:
The observations perfectly correspond to the Bromide ion ($Br^{-}$).
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