



When m-chlorobenzaldehyde is treated with a 50% KOH solution, the reaction that occurs is the Cannizzaro reaction. This is a redox reaction wherein aldehydes without alpha hydrogens undergo simultaneous oxidation and reduction to form a carboxylic acid and an alcohol.
Let's analyze what happens in this reaction:
The balanced chemical reaction is as follows:
\text{2 C}_6\text{H}_4\text{Cl-CHO} + \text{KOH} \rightarrow \text{C}_6\text{H}_4\text{Cl-COONa} + \text{C}_6\text{H}_4\text{Cl-CH}_2\text{OH}\
where:
Hence, one of the products obtained is m-chlorobenzyl alcohol.
The correct option is:
Therefore, the product(s) obtained when m-chlorobenzaldehyde is treated with 50% KOH solution is m-chlorobenzyl alcohol.
The number of \(\pi\)-bonds present in benzoic acid is:
