Question:medium
When copper is heated with conc. $HNO_3$ it produces :
When copper is heated with conc. $HNO_3$ it produces :
Updated On: May 22, 2026
- $Cu(NO_3)_2$ and $NO$
- $Cu(NO_3)_2,NO$ and $NO_2 $
- $Cu(NO_3)_2$ and $N_2O$
- $Cu(NO_3)_2$ and $NO_2$
Show Solution
The Correct Option is D
Solution and Explanation
To solve the given question, let us understand the chemical reaction involved when copper (\(Cu\)) is heated with concentrated nitric acid (\(HNO_3\)).
Reaction of Copper with Concentrated Nitric Acid
The reaction between copper and concentrated nitric acid can be represented by the following chemical equation:
3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 2NO_2 + 4H_2O
- In this reaction, copper metal reacts with concentrated nitric acid to form copper (II) nitrate \((Cu(NO_3)_2)\), nitrogen dioxide gas \((NO_2)\), and water \((H_2O)\).
- Nitrogen dioxide (\(NO_2\)) is a reddish-brown gas, which is a characteristic byproduct of this reaction.
Assessment of the Options
- Cu(NO_3)_2 and NO: Incorrect. This reaction does not typically produce \(NO\) (Nitric Oxide) when concentrated nitric acid is used.
- Cu(NO_3)_2, NO, and NO_2: Incorrect. While \(NO_2\) is produced, \((NO)\) is not typically a product with concentrated nitric acid.
- Cu(NO_3)_2 and N_2O: Incorrect. The formation of \(N_2O\) (Nitrous Oxide) is not favored in this reaction condition.
- Cu(NO_3)_2 and NO_2: Correct. This matches the products of the reaction under study conditions.
Conclusion
Based on the chemical reaction and the analysis of the options, the correct answer is:
Cu(NO_3)_2 and NO_2.
Tip:
When dealing with reactions involving nitric acid, remember that the concentration of the acid can affect the nitrogen oxides produced. Concentrated nitric acid often leads to the formation of \(NO_2\).
Was this answer helpful?
0
Top Questions on p -Block Elements
- $\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is:- JEE Main - 2024
- Chemistry
- p -Block Elements
- $\textbf{Choose the correct statements about the hydrides of group 15 elements.}$
A. The stability of the hydrides decreases in the order \(\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3\)
B. The reducing ability of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
C. Among the hydrides, \(\text{NH}_3\) is a strong reducing agent while \(\text{BiH}_3\) is a mild reducing agent.
D. The basicity of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
Choose the most appropriate from the option given below:- JEE Main - 2024
- Chemistry
- p -Block Elements
- Red lead is:
- BCECE - 2025
- Chemistry
- p -Block Elements
- Which one of these is the most acidic oxide?
- BCECE - 2025
- Chemistry
- p -Block Elements
- Want to practice more? Try solving extra ecology questions todayView All Questions
