Question

When an object is placed at a distance of 40 cm from a convex lens, a real image is formed at a distance V from the lens. If the convex lens is replaced with a concave lens of same focal length, then the change in the position of the image is

• A. $\frac{V(V-40)}{(V-20)}cm$
• B. $\frac{V(V+40)}{(V-20)}cm$
• C. $\frac{V(V-40)}{(V+20)}cm$
• D. $\frac{V(V+40)}{(V+20)}cm$ \bigskip

Hint:

Changing convex to concave flips sign of focal length but object position remains unchanged.

Answer 1

The Correct Option is C