When a dipole placed parallel to electric field is rotating through $π^c$, the work done is W. The work done in rotating the dipole through $(\frac{π}{3})^c$ is
($cos0^{\circ} = 1$, $cos60^{\circ} = \frac{1}{2}$, $cos180^{\circ} = -1$)

Question

The electrostatic potential due to an electric dipole at a distance $ r $ varies as:

Answer 1

Step 1: Express $pE$ in terms of $W$:
From the first rotation, $W = 2pE$, so $pE = \frac W2$.

Step 2: Second rotation:
$W' = pE(1 - \cos 60^{\circ}) = \frac W2 \times \frac12 = \frac W4$.

Final Answer:
$W' = \frac{W}{4}$, option (A). \[ \boxed{\frac{W}{4}} \]

When a dipole placed parallel to electric field is rotating through \(π^c\), the work done is W. The work done in rotating the dipole through \((\frac{π}{3})^c\) is
(\(cos0^{\circ} = 1\), \(cos60^{\circ} = \frac{1}{2}\), \(cos180^{\circ} = -1\))

Show Hint

The Correct Option is A

Solution and Explanation

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When a dipole placed parallel to electric field is rotating through \(π^c\), the work done is W. The work done in rotating the dipole through \((\frac{π}{3})^c\) is(\(cos0^{\circ} = 1\), \(cos60^{\circ} = \frac{1}{2}\), \(cos180^{\circ} = -1\))