Question:medium

What is the value of the ionization energy of hydrogen in joules? (Given that the ionization energy of hydrogen is \( 13.6 \, \text{eV} \))

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Remember: To convert from eV to joules, multiply by \( 1.6 \times 10^{-19} \, \text{J/eV} \). This is useful when dealing with energy calculations in atomic physics.
Updated On: Nov 26, 2025
  • \( 2.18 \times 10^{-18} \, \text{J} \)
  • \( 1.6 \times 10^{-18} \, \text{J} \)
  • \( 3.2 \times 10^{-19} \, \text{J} \)
  • \( 1.0 \times 10^{-19} \, \text{J} \)
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The Correct Option is A

Solution and Explanation

Step 1: Convert ionization energy from eV to joules Use the conversion factor: 1 electronvolt (eV) = \( 1.6 \times 10^{-19} \, \text{J} \). To find the ionization energy of hydrogen in joules, multiply the energy in eV by this conversion factor:\[E_{\text{ionization}} = 13.6 \, \text{eV} \times 1.6 \times 10^{-19} \, \text{J/eV}\]Step 2: Calculate the ionization energy \[E_{\text{ionization}} = 13.6 \times 1.6 \times 10^{-19} = 21.76 \times 10^{-19} = 2.18 \times 10^{-18} \, \text{J}\]Answer: The ionization energy of hydrogen is \( 2.18 \times 10^{-18} \, \text{J} \). The correct answer is option (1).
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