Step 1: Convert ionization energy from eV to joules Use the conversion factor: 1 electronvolt (eV) = \( 1.6 \times 10^{-19} \, \text{J} \). To find the ionization energy of hydrogen in joules, multiply the energy in eV by this conversion factor:\[E_{\text{ionization}} = 13.6 \, \text{eV} \times 1.6 \times 10^{-19} \, \text{J/eV}\]Step 2: Calculate the ionization energy \[E_{\text{ionization}} = 13.6 \times 1.6 \times 10^{-19} = 21.76 \times 10^{-19} = 2.18 \times 10^{-18} \, \text{J}\]Answer: The ionization energy of hydrogen is \( 2.18 \times 10^{-18} \, \text{J} \). The correct answer is option (1).